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Proof step 16 from proof in-mkbag-del (previous step)

count(A[m], mkbag(A, i)) = 0, n < # A, m < # A, n < i, m < i, i ≤ # A ⊦ A[m] = A[n]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 17:
n < i, i ≤ # A, A[n] = a ⊦ count(a, mkbag(A, i)) ≠ 0

Rule argument

spec: <toplevel> name: count-mkbag-non-zero seq: n < i, i ≤ # A, A[n] = a ⊦ count(a, mkbag(A, i)) ≠ 0 subst: [n, i, A, a] → [m, i, A, A[m]] flags: <all paths>

Additional information

Used terms: m, i, A, A[m]