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Proof step 4 from proof index-in-mkbag (previous step)

m < # A, m ≤ n0, ∀ m, A. m < n0 ∧ m < # A → A[m] ∈ mkbag(A, n0) ⊦ A[m] = A[n0], A[m] ∈ mkbag(A, n0)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: m, A

Additional information

Used simplifier rules: ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m ≤ n → (n ≤ m ↔ m = n); (s) Used terms: m, A