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Proof step 2 from proof mkbag-size (previous step)

∀ A. # mkbag(A, n0) = n0 ⊦ # mkbag(A, n0 +1) = n0 +1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
∀ A. # mkbag(A, n0) = n0 ⊦ # mkbag(A, n0) = n0

Rule argument

Additional information

Used simplifier rules: mkbag-rec: ⊦ mkbag(A, n + 1) = mkbag(A, n) ++ A[n];% ⊦ m + n = m + n0 ↔ n = n0; (s)% ⊦ #(bag ++ a) = # bag + 1; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m +1 = m + 1; (s)