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Proof step 1 from proof sorted-shift-one (conclusion)

n ≤ m, m + 1 < n0 ⊦ m + 1 < # A ∧ sorted(A, n, n0) → sorted(A[m + 1, A[m]], n, n0)

System applied rule normalize

And obtained the following new goals

Proof step 2:
m + 1 < # A, m + 1 < n0, sorted(A, n, n0), n ≤ m ⊦ sorted(A[m + 1, A[m]], n, n0)

Rule argument

Additional information