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Proof step 11 from proof sorted-shift-one (previous step)

m + 1 < # A, m + 1 < n0, n1 + 1 < # A, n1 + 1 < n0, A[n1 + 1] < A[n1], n ≤ n1, n0 ≤ # A, n ≤ m, ∀ n1. n ≤ n1 ∧ n1 + 1 < n0 → ¬ A[n1 + 1] < A[n1] ⊦ n1 = m + 1, n1 = m

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 9 terms: n1

Additional information

Used terms: n1