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Proof step 1 from proof inv-init (conclusion)

n > 0 ⊦ ⟪caterpillar_init#(n; ; h, xs, xs_len, ys)⟫ (# xs < h ∧ # xs = xs_len ∧ (# ys = 0 ∨ # ys = h))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
n ≠ 0 ⊦ ⟪caterpillar_init#(n; ; h, xs, xs_len, ys)⟫ (# xs < h ∧ # xs = xs_len ∧ (ys = [] ∨ # ys = h))

Rule argument

Additional information

Used simplifier rules: ⊦ # x = 0 ↔ x = []; (s)% ⊦ 0 < m ↔ m ≠ 0; (s)% ⊦ m > n ↔ n < m; (s)