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Proof step 3 from proof inv-init (previous step)

⊦ ⟪if n > 0 then h := n, xs := [], xs_len := 0, ys := [] else abort⟫ (# xs < h ∧ # xs = xs_len ∧ (ys = [] ∨ # ys = h)), n = 0

Heuristic symbolic execution applied rule if positive right

And obtained the following new goals

Proof step 4:
⊦ ⟪h := n, xs := [], xs_len := 0, ys := []⟫ (# xs < h ∧ # xs = xs_len ∧ (ys = [] ∨ # ys = h)), n = 0

Rule argument

pos: right 1

Additional information

Used simplifier rules: ⊦ m > n ↔ n < m; (s)% ⊦ 0 < m ↔ m ≠ 0; (s)