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Proof step 5 from proof initialization (previous step)

⊦ ⟨caterpillar_init#(n; ; h1, xs1, xs_len, ys)⟩ (prefixn(h1, xs1 + ys) = prefixn(h1, []) ∧ # xs1 + # ys ≤ # [] ∧ n = h1), n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
n ≠ 0 ⊦ ⟨caterpillar_init#(n; ; h1, xs1, xs_len, ys)⟩ (prefixn(h1, xs1 + ys) = [] ∧ # xs1 + # ys = 0 ∧ n = h1)

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ 0 ↔ m = 0; (s)% ⊦ # [] = 0; (s)% ⊦ prefixn(n, []) = []; (s)