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Proof step 1 from proof prefixn-shorter (conclusion)

⊦ prefixn(n + 1, x0) = prefixn(n + 1, x1) → (prefixn(n, x0) = prefixn(n, x1) ↔ true)

System applied rule normalize

And obtained the following new goals

Proof step 2:
prefixn(n + 1, x0) = prefixn(n + 1, x1) ⊦ prefixn(n, x0) = prefixn(n, x1) ↔ true

Rule argument

Additional information