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Proof step 13 from proof ex-p (previous step)

P(H0), xP(x)(H1), H1 ⊥ H0 ⊦ ∃ x. xP(x)(H1)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: x

Additional information

Used terms: x