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Proof step 10 from proof initialization (previous step)

n0 = n ⊦ ⟪H := ∅⟫ ⟨caterpillar_init#(n; ; h0, xs, xs_len0, ys)⟩ ∃ n. ((ls(null, xs) * ls(null, ys) * del-list([], n)))(H) ∧ n ≤ # xs + # ys ∧ n + # xs ≤ h0 ∧ n0 = h0 ∧ 0 = xs_len0, n = 0

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Proof step 11:
n0 = n ⊦ ⟨caterpillar_init#(n; ; h0, xs, xs_len0, ys)⟩ ∃ n. ((ls(null, xs) * ls(null, ys) * del-list([], n)))(∅) ∧ n ≤ # xs + # ys ∧ n + # xs ≤ h0 ∧ n0 = h0 ∧ 0 = xs_len0, n = 0

Proof step 10 from proof initialization (previous step)

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Rule argument

Additional information