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Proof step 19 from proof process-one (previous step)

m = n0 + # y, ((r => a0 × r0 * ls(r0, y) * del-list(rx0, n0) * P))(H), # y ≤ m ⊦ r = null, r0 = null, ((del-list(r0 ' + rx0, m) * P))(H -- r)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
((r => a0 × r0 * ls(r0, y) * del-list(rx0, n0) * P))(H) ⊦ r = null, r0 = null, ((del-list(r0 ' + rx0, n0 + # y) * P))(H -- r)

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m ≤ m + n; (s)