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Proof step 11 from proof process-queue (previous step)

((del-list(to_delete, n) * P))(H) ⊦ ⟪tree_buffer_heap_process_one#(; H, to_delete)⟫ ((n ≥ 1 → ((del-list(to_delete, n - 1) * P))(H)) ∧ (n = 0 → to_delete = [] ∧ ((del-list([], 0) * P))(H)))

Proof step 11 from proof process-queue (previous step)

Lemma process-one