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Proof step 8 from proof process-queue (previous step)

((del-list(to_delete, n) * P))(H), 1 ≤ n → ((del-list(to_delete0, n - 1) * P))(H0), n = 0 → to_delete0 = [] ∧ P(H0) ⊦ ⟪tree_buffer_heap_process_one#(; H0, to_delete0)⟫ ((2 ≤ n → ((del-list(to_delete0, n - 2) * P))(H0)) ∧ (n < 2 → to_delete0 = [] ∧ P(H0)))

User applied rule cut formula

And obtained the following new goals

Proof step 9:
n = 0, ((del-list(to_delete, n) * P))(H), n = 0 → to_delete0 = [] ∧ P(H0), 1 ≤ n → ((del-list(to_delete0, n - 1) * P))(H0) ⊦ ⟪tree_buffer_heap_process_one#(; H0, to_delete0)⟫ ((2 ≤ n → ((del-list(to_delete0, n - 2) * P))(H0)) ∧ (n < 2 → to_delete0 = [] ∧ P(H0)))
Proof step 12:
((del-list(to_delete, n) * P))(H), n = 0 → to_delete0 = [] ∧ P(H0), 1 ≤ n → ((del-list(to_delete0, n - 1) * P))(H0) ⊦ ⟪tree_buffer_heap_process_one#(; H0, to_delete0)⟫ ((2 ≤ n → ((del-list(to_delete0, n - 2) * P))(H0)) ∧ (n < 2 → to_delete0 = [] ∧ P(H0))), n = 0

Rule argument

fma: n = 0

Additional information

Used formulas: n = 0