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Proof step 12 from proof aligndown-aligndown-add (conclusion)

n ≠ 0 ⊦ align↓(align↓(n0, n) + n1, n) = align↓(n0, n) + align↓(n1, n)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
0 ≠ m ⊦ align↓(n, m) = (n % m = 0 ⊃ n;n / m * m)

Rule argument

Additional information

[Concretesimprules((Csimpnamedseq(aligndown-def,,, 0 ≠ m ⊦ align↓(n, m) = (n % m = 0 ⊃ n;n / m * m))))]