[Imprint][Data Privacy Statement][E-Mail]

View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 11 from proof rounded-help (previous step)

m * n / m + m ≤ n ⊦ m = 0

User applied rule structural induction

And obtained the following new goals

Proof step 10:
∀ m. m * n0 / m + m ≤ n0 → m = 0, m * n0 +1 / m + m ≤ n0 +1 ⊦ m = 0

Rule argument

indvar: n

Additional information

[Concretesimprules((Csimpgen(nat freely generated by 0, +1;) Csimpnamedseq(nat-div,,zero,n ≠ 0 ⊦ 0 / n = 0) Csimpnamedseq(nat-mult,,mult-base, ⊦ m * 0 = 0) Csimpnamedseq(nat-mult,,mult-a, ⊦ m0 * m * n = (m0 * m) * n) Csimpnamedseq(nat-mult,,mult-c, ⊦ m * n = n * m) Csimpnamedseq(nat-basic2,,add-base, ⊦ n + 0 = n) Csimpnamedseq(nat-basic2,,a, ⊦ (m + n0) + n1 = m + n0 + n1) Csimpnamedseq(nat-basic2,,c, ⊦ m + n = n + m) Csimpnamedseq(nat,,lez-01, ⊦ m ≤ 0 ↔ m = 0)))]