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Proof step 36 from proof copy2append (previous step)

n1 + m ≤ # ar1, n0 + m ≤ # ar0 ⊦ copy(ar0, n0, ar1, n1, m) = subarray(ar1, 0, n1) + subarray(ar0, n0, m) + subarray(ar1, n1 + m, # ar1 - n1 - m)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 35:
# ar1 - n1 = n2 + m ∧ m ≤ # ar1 - n1, n1 + m ≤ # ar1, n0 + m ≤ # ar0 ⊦ copy(ar0, n0, ar1, n1, m) = subarray(ar1, 0, n1) + subarray(ar0, n0, m) + subarray(ar1, n1 + m, n2)

Rule argument

spec: nat inst: name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [# ar1 - n1, m, n] flags:

Additional information

[Concretesimprules((Csimpnamedseq(nat,,lels-01, ⊦ ¬ m ≤ n ↔ n < m) Csimpnamedforward(nat,,fle-01, ⊦ m ≤ n ∧ n < n0 → m < n0) Csimpnamedforward(nat-basic1,,f, ⊦ m < n → n ≠ 0) Csimpnamedseq(nat-basic2,,l-02, ⊦ ¬ m + n < m) Csimpnamedseq(nat-basic2,,a, ⊦ (m + n0) + n1 = m + n0 + n1) Csimpnamedseq(nat-basic2,,c, ⊦ m + n = n + m) Csimpnamedseq(nat,,ls-02, n0 ≤ n ⊦ m ≤ n - n0 ↔ m + n0 ≤ n) Csimpnamedseq(nat,,le-ls-simp, ⊦ m ≤ n → (n < m ↔ false)) Csimpelim(n ≤ m ⊦ n0 = m - n ↔ m = n0 + n))), Extraterms((# ar1 - n1mn))]