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Proof step 10 from proof copy2append00 (conclusion)

⊦ n ≤ # ar0 ∧ n ≤ # ar1 → copy(ar1, 0, ar0, 0, n) = subarray(ar1, 0, n) + subarray(ar0, n, # ar0 - n)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
n ≤ # ar1, n ≤ # ar0 ⊦ copy(ar1, 0, ar0, 0, n) = subarray(ar1, 0, n) + subarray(ar0, n, # ar0 - n)

Rule argument

Additional information

[Concretesimprules(())]