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Proof step 41 from proof range-copy-upper (previous step)

m1 ≤ n3 + m0, n3 ≤ m1, n3 + n1 ≤ # ar0, n1 ≤ # ar0, n1 + m1 ≤ # ar0, (n3 + n1) + m0 ≤ # ar0, n + m0 ≤ # ar ⊦ range=(ar2, n2, copy(ar, n, ar0, n3 + n1, m0), n1, m1) ↔ range=(ar2, n2, ar0, n1, n3) ∧ range=(ar2, n3 + n2, ar, n, m1 - n3)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 40:
m1 = n0 + n3, m1 ≤ n3 + m0, n3 ≤ m1, n3 + n1 ≤ # ar0, n1 ≤ # ar0, n1 + m1 ≤ # ar0, (n3 + n1) + m0 ≤ # ar0, n + m0 ≤ # ar ⊦ range=(ar2, n2, copy(ar, n, ar0, n3 + n1, m0), n1, m1) ↔ range=(ar2, n2, ar0, n1, n3) ∧ range=(ar2, n3 + n2, ar, n, n0)

Rule argument

spec: nat inst: name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [m1, n3, n0] flags:

Additional information

[Concretesimprules((Csimpelim(n ≤ m ⊦ n0 = m - n ↔ m = n0 + n))), Extraterms((m1n3n0))]