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Proof step 5 from proof range-eq-append (previous step)

⊦ range=(ar0, n0, ar1, n1, 0 + m1) ↔ range=(ar0, n0, ar1, n1, 0) ∧ range=(ar0, n0 + 0, ar1, n1 + 0, m1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
range=(ar0, n0, ar1, n1, m1) ⊦ range=(ar0, n0, ar1, n1, 0)

Rule argument

Additional information

[Concretesimprules((Csimpnamedseq(nat-basic2,,c, ⊦ m + n = n + m) Csimpnamedseq(nat-basic2,,a, ⊦ (m + n0) + n1 = m + n0 + n1) Csimpnamedseq(nat-basic2,,add-base, ⊦ n + 0 = n)))]