[Imprint][Data Privacy Statement][E-Mail]

View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 17 from proof range-eq-ext (conclusion)

⊦ range=(ar0, n0, ar1, n1, m) ↔ n0 + m ≤ # ar0 ∧ n1 + m ≤ # ar1 ∧ (∀ n. n < m → ar0[n0 + n] = ar1[n1 + n])

User applied rule structural induction

And obtained the following new goals

Proof step 1:
⊦ range=(ar0, n0, ar1, n1, 0) ↔ n0 ≤ # ar0 ∧ n1 ≤ # ar1

Rule argument

indvar: m

Additional information

[Concretesimprules((Csimpnamedseq(range-eq-0,,, ⊦ range=(ar0, n0, ar1, n1, 0) ↔ n0 ≤ # ar0 ∧ n1 ≤ # ar1) Csimpgen(nat freely generated by 0, +1;) Csimpnamedseq(nat-basic2,,add-base, ⊦ n + 0 = n) Csimpnamedseq(nat-basic2,,a, ⊦ (m + n0) + n1 = m + n0 + n1) Csimpnamedseq(nat-basic2,,c, ⊦ m + n = n + m) Csimpnamedseq(nat-basic1,,zero-01, ⊦ ¬ m < 0)))]