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Proof step 13 from proof range-eq-trans (conclusion)

⊦ range=(ar0, n0, ar1, n1, m) ∧ range=(ar1, n1, ar2, n2, m) → (¬ range=(ar0, n0, ar2, n2, m) ↔ false)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
range=(ar0, n0, ar1, n1, m), range=(ar1, n1, ar2, n2, m) ⊦ range=(ar0, n0, ar2, n2, m)

Rule argument

Additional information

[Concretesimprules(())]