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Proof step 13 from proof subarray-append-elim-left (conclusion)

⊦ # ar0 = n0 ∧ n1 + m ≤ # ar1 → subarray(ar0 + ar1, n0 + n1, m) = subarray(ar1, n1, m)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
n1 + m ≤ # ar1 ⊦ subarray(ar0 + ar1, # ar0 + n1, m) = subarray(ar1, n1, m)

Rule argument

Additional information

[Concretesimprules(())]