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Proof step 14 from proof subarray-append-left-01 (previous step)

m ≤ # ar0 ⊦ subarray(ar0 + ar1, 0, m) = subarray(ar0, 0, m)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ ar1 = ar2 ↔ # ar1 = # ar2 ∧ (∀ n. n < # ar1 → ar1[n] = ar2[n])

Rule argument

spec: array inst: name: Extension seq: ⊦ ar1 = ar2 ↔ # ar1 = # ar2 ∧ (∀ n. n < # ar1 → ar1[n] = ar2[n]) subst: [ar2, ar1] → [subarray(ar0, 0, m), subarray(ar0 + ar1, 0, m)] flags: rewrite

Additional information

[Concretesimprules(()), Extraterms((subarray(ar0, 0, m)subarray(ar0 + ar1, 0, m)))]