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Proof step 27 from proof emptystream-cancel (previous step)

# σ = ⌜n⌝ ⊦ σ + σ⊥ = σ⊥ ↔ σ = σ⊥ to n

User applied rule case distinction

And obtained the following new goals

Proof step 19:
σ + σ⊥ = σ⊥, # σ = ⌜n⌝ ⊦ σ = σ⊥ to n

Rule argument

pos: right 1

Additional information

[Concretesimprules(())]