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Proof step 2 from proof eaccess (conclusion)

⊦ ¬ ⌊EACCESS⌋

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ ⌊err⌋ ↔ err ≠ ESUCCESS ∧ err ≠ EEXISTS ∧ err ≠ ENOENT ∧ err ≠ EISDIR ∧ err ≠ ENOTEMPTY ∧ err ≠ ENOTDIR ∧ err ≠ EBADFD ∧ err ≠ EACCESS

Rule argument

Additional information

[Concretesimprules((Csimpnamedseq(class,,, ⊦ ⌊err⌋ ↔ err ≠ ESUCCESS ∧ err ≠ EEXISTS ∧ err ≠ ENOENT ∧ err ≠ EISDIR ∧ err ≠ ENOTEMPTY ∧ err ≠ ENOTDIR ∧ err ≠ EBADFD ∧ err ≠ EACCESS) Csimpnamedseq(error,,disj-01, ⊦ EBADFD ≠ EACCESS) Csimpnamedseq(error,,disj-02, ⊦ ENOTDIR ≠ EACCESS) Csimpnamedseq(error,,disj-46, ⊦ ENOTEMPTY ≠ EACCESS) Csimpnamedseq(error,,disj-04, ⊦ EISDIR ≠ EACCESS) Csimpnamedseq(error,,disj-07, ⊦ ENOENT ≠ EACCESS) Csimpnamedseq(error,,disj-11, ⊦ EEXISTS ≠ EACCESS) Csimpnamedseq(error,,disj-29, ⊦ ESUCCESS ≠ EACCESS)))]