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Proof step 2 from proof einval (conclusion)

⊦ ⌊EINVAL⌋

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ ⌊err⌋ ↔ err ≠ ESUCCESS ∧ err ≠ EEXISTS ∧ err ≠ ENOENT ∧ err ≠ EISDIR ∧ err ≠ ENOTEMPTY ∧ err ≠ ENOTDIR ∧ err ≠ EBADFD ∧ err ≠ EACCESS

Rule argument

spec: inst: name: class seq: ⊦ ⌊err⌋ ↔ err ≠ ESUCCESS ∧ err ≠ EEXISTS ∧ err ≠ ENOENT ∧ err ≠ EISDIR ∧ err ≠ ENOTEMPTY ∧ err ≠ ENOTDIR ∧ err ≠ EBADFD ∧ err ≠ EACCESS subst: [err] → [EINVAL] flags: rewrite, current

Additional information

[Concretesimprules((Csimpnamedseq(error,,disj-78, ⊦ ESUCCESS ≠ EINVAL) Csimpnamedseq(error,,disj-73, ⊦ EEXISTS ≠ EINVAL) Csimpnamedseq(error,,disj-72, ⊦ ENOENT ≠ EINVAL) Csimpnamedseq(error,,disj-71, ⊦ EISDIR ≠ EINVAL) Csimpnamedseq(error,,disj-69, ⊦ ENOTEMPTY ≠ EINVAL) Csimpnamedseq(error,,disj-70, ⊦ ENOTDIR ≠ EINVAL) Csimpnamedseq(error,,disj-68, ⊦ EBADFD ≠ EINVAL) Csimpnamedseq(error,,disj-67, ⊦ EACCESS ≠ EINVAL))), Extraterms((EINVAL))]