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Proof step 5 from proof prefix-append-one-sizeeq (
previous step
)
# x0 = # x1 + 1, x0 ⊑ x1 + a ' ⊦ x0 = x1 + a '
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 1
:
⊦ x ⊑ y ↔ (∃ z. x + z = y)
Rule argument
spec: list-last inst: name: prefix seq: ⊦ x ⊑ y ↔ (∃ z. x + z = y) subst: [y, x] → [x1 + a ', x0] flags: rewrite
Additional information
[Concretesimprules(()), Extraterms((x1 + a 'x0))]