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Proof step 6 from proof ex-notin (previous step)

ns.max + 1 ∈ ns ⊦ ns = ∅, # ns = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ ns.max < n ∧ ns ≠ ∅ → ¬ n ∈ ns

Rule argument

spec: oset inst: nat-set name: max-gr seq: ⊦ ns.max < n ∧ ns ≠ ∅ → ¬ n ∈ ns subst: [ns, n] → [ns, ns.max + 1] flags: rewrite

Additional information

[Concretesimprules(()), Extraterms((nsns.max + 1))]