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Proof step 8 from proof ex-smallest-notin (conclusion)

⊦ ∃ n. ¬ n ∈ ns ∧ (∀ m. ¬ m ∈ ns → n ≤ m)

User applied rule insert lemma

And obtained the following new goals

Rule argument

spec: inst: name: ex-notin seq: ⊦ ∃ n. ¬ n ∈ ns subst: [ns] → [ns] flags: current, []

Additional information

[Concretesimprules(()), Extraterms((ns))]