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Proof step 11 from proof subset-put-strong-03 (previous step)

st ⊆ st0 ⊦ st[a, d] ⊆ st0[a, d]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ st1 ⊆ st2 ↔ (∀ a. a ∈ st1 → a ∈ st2 ∧ st1[a] = st2[a])

Rule argument

spec: inst: name: Subset seq: ⊦ st1 ⊆ st2 ↔ (∀ a. a ∈ st1 → a ∈ st2 ∧ st1[a] = st2[a]) subst: [st2, st1] → [st0[a, d], st[a, d]] flags: rewrite, current

Additional information

[Concretesimprules(()), Extraterms((st0[a, d]st[a, d]))]