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Proof step 20 from proof arrayMaxWhile (previous step)

getintarray(a, st) ≠ [] → max(getintarray(a, st)) ∈ getintarray(a, st) ∧ (∀ i. i ∈ getintarray(a, st) → i ≤ max(getintarray(a, st))), st[a -- i1 '] .intval = max(getintarray(a, st)), st[_mode] = noval, st[a -- i0 '] .intval ≤ st[a -- i2 '] .intval, 0 < st[a -- _length] .intval, 1 < st[a -- _length] .intval, i1 < st[a -- _length] .intval, is_integervalue(st[a -- i0 ']), is_integervalue(st[a -- 0 ']), is_integervalue(st[a -- i2 ']), is_integervalue(st[a -- i1 ']), 0 ≤ i2, init(st), okarray(a, int_type, st), i0 ≤ i1, i1 ≤ i2, 0 ≤ i0, 0 ≤ i1, i0 < i2, 0 < i2, is_integervalue(st[a -- 1 ']), i0 < st[a -- _length] .intval, i2 < st[a -- _length] .intval ⊦ i0 = i2, getintarray(a, st) = [], a = jvmref, ∃ i3. ¬ i3 ≤ i0 ∧ i3 ≤ i2 ∧ st[a -- i3 '] .intval = max(getintarray(a, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
st[a -- i1 '] .intval = max(getintarray(a, st)), st[_mode] = noval, st[a -- i0 '] .intval ≤ st[a -- i2 '] .intval, 0 < st[a -- _length] .intval, 1 < st[a -- _length] .intval, i1 < st[a -- _length] .intval, is_integervalue(st[a -- i0 ']), is_integervalue(st[a -- 0 ']), is_integervalue(st[a -- i2 ']), is_integervalue(st[a -- i1 ']), 0 ≤ i2, init(st), okarray(a, int_type, st), i0 ≤ i1, i1 ≤ i2, 0 ≤ i0, 0 ≤ i1, i0 < i2, 0 < i2, is_integervalue(st[a -- 1 ']), i0 < st[a -- _length] .intval, i2 < st[a -- _length] .intval, max(getintarray(a, st)) ∈ getintarray(a, st), ∀ i. i ∈ getintarray(a, st) → i ≤ max(getintarray(a, st)) ⊦ i0 = i2, getintarray(a, st) = [], a = jvmref, ∃ i3. ¬ i3 ≤ i0 ∧ i3 ≤ i2 ∧ st[a -- i3 '] .intval = max(getintarray(a, st))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]