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Proof step 30 from proof arrayMaxWhile (previous step)

st[_mode] = noval, st[a -- i1 '] .intval = max(getintarray(a, st)), 0 < st[a -- _length] .intval, 1 < st[a -- _length] .intval, i1 < st[a -- _length] .intval, is_integervalue(st[a -- i0 ']), is_integervalue(st[a -- 0 ']), is_integervalue(st[a -- i2 ']), is_integervalue(st[a -- i1 ']), 0 ≤ i2, init(st), okarray(a, int_type, st), i0 ≤ i1, i1 ≤ i2, 0 ≤ i0, 0 ≤ i1, i0 < i2, 0 < i2, is_integervalue(st[a -- 1 ']), i0 < st[a -- _length] .intval, i2 < st[a -- _length] .intval, st[a -- i2 '] .intval < st[a -- i0 '] .intval ⊦ i0 = i2, getintarray(a, st) = [], a = jvmref, i0 ≤ i1 ∧ ¬ i2 ≤ i1 ∧ st[a -- i1 '] .intval = max(getintarray(a, st)), ∃ i3. i0 ≤ i3 ∧ ¬ i2 ≤ i3 ∧ st[a -- i3 '] .intval = max(getintarray(a, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 29:
st[_mode] = noval, st[a -- i2 '] .intval = max(getintarray(a, st)), 0 ≤ i0, i0 < i2, 0 < i2, is_integervalue(st[a -- 1 ']), i0 < st[a -- _length] .intval, max(getintarray(a, st)) < st[a -- i0 '] .intval, 0 < st[a -- _length] .intval, 1 < st[a -- _length] .intval, i2 < st[a -- _length] .intval, is_integervalue(st[a -- i0 ']), is_integervalue(st[a -- 0 ']), is_integervalue(st[a -- i2 ']), 0 ≤ i2, init(st), okarray(a, int_type, st) ⊦ i0 = i2, getintarray(a, st) = [], a = jvmref, ∃ i3. i0 ≤ i3 ∧ ¬ i2 ≤ i3 ∧ st[a -- i3 '] .intval = max(getintarray(a, st))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i ≠ j → (i ≤ j ↔ i < j)], [CSIMPSEQ : ⊦ i ≤ i], [CSIMPSEQ : ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j], [CSIMPFORWARD : ⊦ i < i0 ∧ i = i1 → i1 < i0], [CSIMPSEQ : ⊦ i ≤ j → (j ≤ i ↔ i = j)])]]