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Proof step 45 from proof arrayMaxWhile (previous step)

a0 = a, st[_mode] = noval, st[a -- i1 '] .intval = max(getintarray(a, st)), m = i→n(i2 - i0), boolvar0 ↔ i0 ≠ i2, getintarray(a, st) ≠ [], is_integervalue(st[a -- i1 ']), i0 < st[a -- _length] .intval, 0 ≤ i2, 0 < st[a -- _length] .intval, init(st), okarray(a, int_type, st), i0 ≤ i1, i1 ≤ i2, i2 < st[a -- _length] .intval, 0 ≤ i0, 0 ≤ i1, i0 ≤ i2, i1 < st[a -- _length] .intval, is_integervalue(st[a -- i0 ']), is_integervalue(st[a -- 0 ']), is_integervalue(st[a -- i2 ']) ⊦ 〈st; if (boolvar0) { if (a0[i0] <= a0[i2]) i0++; else i2--; } else { }〉 ( ( boolvar0 ∧ st[_mode] = noval → init(st) ∧ okarray(a, int_type, st) ∧ getintarray(a, st) ≠ [] ∧ 0 ≤ i0 ∧ (∃ i. i0 ≤ i ∧ i ≤ i2 ∧ i2 < st[a0 -- _length] .intval ∧ st[a -- i '] .intval = max(getintarray(a, st))) ∧ i→n(i2 - i0) < m) ∧ (¬ boolvar0 ∨ st[_mode] ≠ noval → 〈st; i = i0; 〉 (st[a -- i '] .intval = max(getintarray(a, st)) ∧ 0 ≤ i ∧ i < st[a -- _length] .intval)))

Heuristic simple java stuff applied rule jif

And obtained the following new goals

Proof step 42:
a0 = a, st[_mode] = noval, st[a -- i1 '] .intval = max(getintarray(a, st)), m = i→n(i2 - i0), boolvar0 ↔ i0 ≠ i2, getintarray(a, st) ≠ [], is_integervalue(st[a -- i1 ']), i0 < st[a -- _length] .intval, 0 ≤ i2, 0 < st[a -- _length] .intval, init(st), okarray(a, int_type, st), i0 ≤ i1, i1 ≤ i2, i2 < st[a -- _length] .intval, 0 ≤ i0, 0 ≤ i1, i0 ≤ i2, i1 < st[a -- _length] .intval, is_integervalue(st[a -- i0 ']), is_integervalue(st[a -- 0 ']), is_integervalue(st[a -- i2 ']), st[_mode] = noval, boolvar0 ⊦ 〈st; i3 = a0[i0]; 〉〈st; i4 = a0[i2]; 〉〈st; boolvar = i3 ≤ i4; 〉〈st; if (boolvar) i0++; else i2--; 〉 ( ( boolvar0 ∧ st[_mode] = noval → init(st) ∧ okarray(a, int_type, st) ∧ getintarray(a, st) ≠ [] ∧ 0 ≤ i0 ∧ (∃ i. i0 ≤ i ∧ i ≤ i2 ∧ i2 < st[a0 -- _length] .intval ∧ st[a -- i '] .intval = max(getintarray(a, st))) ∧ i→n(i2 - i0) < m) ∧ (¬ boolvar0 ∨ st[_mode] ≠ noval → 〈st; i = i0; 〉 (st[a -- i '] .intval = max(getintarray(a, st)) ∧ 0 ≤ i ∧ i < st[a -- _length] .intval)))
Proof step 44:
a0 = a, st[_mode] = noval, st[a -- i1 '] .intval = max(getintarray(a, st)), m = i→n(i2 - i0), boolvar0 ↔ i0 ≠ i2, getintarray(a, st) ≠ [], is_integervalue(st[a -- i1 ']), i0 < st[a -- _length] .intval, 0 ≤ i2, 0 < st[a -- _length] .intval, init(st), okarray(a, int_type, st), i0 ≤ i1, i1 ≤ i2, i2 < st[a -- _length] .intval, 0 ≤ i0, 0 ≤ i1, i0 ≤ i2, i1 < st[a -- _length] .intval, is_integervalue(st[a -- i0 ']), is_integervalue(st[a -- 0 ']), is_integervalue(st[a -- i2 ']), st[_mode] = noval, ¬ boolvar0 ⊦ ( boolvar0 ∧ st[_mode] = noval → init(st) ∧ okarray(a, int_type, st) ∧ getintarray(a, st) ≠ [] ∧ 0 ≤ i0 ∧ (∃ i. i0 ≤ i ∧ i ≤ i2 ∧ i2 < st[a0 -- _length] .intval ∧ st[a -- i '] .intval = max(getintarray(a, st))) ∧ i→n(i2 - i0) < m) ∧ (¬ boolvar0 ∨ st[_mode] ≠ noval → 〈st; i = i0; 〉 (st[a -- i '] .intval = max(getintarray(a, st)) ∧ 0 ≤ i ∧ i < st[a -- _length] .intval))

Rule argument

[fmapos-arg: pos: right 1]

Additional information

[[CONCRETESIMPRULES : ()]]