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Proof step 46 from proof challenge3a (previous step)

ar[m] = ar[n], n < # ar, n < m, m < # ar, n + 1 < # ar, ar[m1] ≠ ar[n2] ∨ m1 = n2 ∨ ¬ m1 < # ar ∨ ¬ n2 < # ar, n < # ar → (∀ n0. n < n0 ∧ n0 < # ar → ar[n] ≠ ar[n0]) ⊦ m = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 45:
ar[m] = ar[n], n < # ar, n < m, m < # ar, n + 1 < # ar, ar[m1] ≠ ar[n2] ∨ m1 = n2 ∨ ¬ m1 < # ar ∨ ¬ n2 < # ar, ∀ n0. n < n0 ∧ n0 < # ar → ar[n] ≠ ar[n0] ⊦ m = n

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]