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Proof step 45 from proof challenge3b (
previous step
)
ar[m] = ar[n], n < # ar, n < m, m < # ar, n + 1 < # ar, ar[m1] ≠ ar[n2] ∨ ar[m1] = a ∨ m1 = n2 ∨ ¬ m1 < # ar ∨ ¬ n2 < # ar, ∀ n0. n < n0 ∧ n0 < # ar → ar[n] ≠ ar[n0] ⊦ ar[n] = a, m = n
User applied rule all left
And closed the goal!
Rule argument
[EXRARG : pos: left 7, [extquanttermlist: (m)abort:F, discard:T, computed:T]]
Additional information
[[CONCRETESIMPRULES : ()], [EXTRATERMS : (m)]]