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Proof step 8 from proof add-at-05 (previous step)

is_fskey(sk), 0 < i, ∀ r0, st, val, r, sk, i0. i→n(i0) < i→n(i) → (is_fskey(sk) → (addarray(r, val, i0, st)[r0 -- sk]) = st[r0 -- sk]) ⊦ (((r0 = r ∧ sk = (i - 1) ') ⊃ val; addarray(r, val, i - 1, st)[r0 -- sk])) = st[r0 -- sk]

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 7:
i = i1 + 1, is_fskey(sk), 0 < i, ∀ r0, st, val, r, sk, i0. i→n(i0) < i→n(i) → (is_fskey(sk) → (addarray(r, val, i0, st)[r0 -- sk]) = st[r0 -- sk]) ⊦ (((r0 = r ∧ sk = i1 ') ⊃ val; addarray(r, val, i1, st)[r0 -- sk])) = st[r0 -- sk]

Rule argument

[speclemmaarg: ,i0 = i - j ↔ i = i0 + j ,[i, j, i0] → [i, 1, i1] ,T ,int-abs , ,elim-sub ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ i0 = i - j ↔ i = i0 + j])], [EXTRATERMS : (i, 1, i1)]]