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Proof step 5 from proof add-at-neg (previous step)

¬ vals ≠ [], i < 0, ∀ st, ty, r, i, vals0. # vals0 < # vals → (i < 0 → (addarray(r, ty, vals0, st)[r -- i ']) = st[r -- i ']) ⊦ (addarray(r, ty, vals, st)[r -- i ']) = st[r -- i ']

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
i < 0, ∀ st, ty, r, i, vals0. # vals0 < # [] → (i < 0 → (addarray(r, ty, vals0, st)[r -- i ']) = st[r -- i ']) ⊦ (addarray(r, ty, [], st)[r -- i ']) = st[r -- i ']

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]