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Proof step 7 from proof add-at-neg (previous step)

i ≠ n→i(m), # vals = m + 1, i < 0, ∀ st, ty, r, i, vals0. # vals0 < m + 1 → (i < 0 → (addarray(r, ty, vals0, st)[r -- i ']) = st[r -- i ']) ⊦ (addarray(r, ty, vals .butlast, st)[r -- i ']) = st[r -- i '], vals = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
# vals = m + 1, i < 0, ∀ st, ty, r, i, vals0. # vals0 < m + 1 → (i < 0 → (addarray(r, ty, vals0, st)[r -- i ']) = st[r -- i ']) ⊦ i = n→i(m), vals = [], (addarray(r, ty, vals .butlast, st)[r -- i ']) = st[r -- i ']

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]