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Proof step 3 from proof add-at-ok (conclusion)

⊦ 0 ≤ i ∧ i < n→i(# vals) → (addarray(r, ty, vals, st)[r -- i ']) = vals[i→n(i)]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ addarray(r, ty, vals, st) = addarray(r, vals, 0, st[r -- _type, typeval(mkarraytype(ty))][r -- _length, intval(n→i(# vals))])
Proof step 2:
⊦ 0 ≤ i ∧ i < n→i(# vals) → (addarray(r, vals, 0, st)[r -- i ']) = vals[i→n(i)]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]