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Proof step 18 from proof add-okarray (conclusion)

⊦ r ≠ val .refval → (okarray(val, ty0, i, addarray(r, ty, vals, st)) ↔ okarray(val, ty0, i, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
⊦ r = val .refval, okarray(val, ty0, i, addarray(r, ty, vals, st)) ↔ okarray(val, ty0, i, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]