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Proof step 14 from proof add-put-switch (conclusion)

⊦ is_fskey(sk) ∨ r ≠ r0 → addarray(r, val, i, st[r0 -- sk, val0]) = (addarray(r, val, i, st)[r0 -- sk, val0])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ r ≠ r0 → (addarray(r, val0, i, st)[r0 -- sk, val]) = addarray(r, val0, i, st[r0 -- sk, val])
Proof step 13:
is_fskey(sk) ⊦ addarray(r0, val, i, st[r0 -- sk, val0]) = (addarray(r0, val, i, st)[r0 -- sk, val0])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]