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Proof step 24 from proof addarray-addaray (previous step)

0 ≤ i0 ∧ i0 < n→i(# mklist(initial_value(ty), i→n(i))), 0 ≤ i, i0 < i, 0 < i, 0 ≤ i0 ⊦ initial_value(ty) = (mklist(initial_value(ty), i→n(i))[i→n(i0)])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
0 ≤ i, 0 < i, 0 ≤ i0, i0 < i ⊦ initial_value(ty) = (mklist(initial_value(ty), i→n(i))[i→n(i0)])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ 0 < i → n→i(i→n(i)) = i], [CSIMPSEQ : ⊦ # mklist(val, n) = n])]]