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Proof step 56 from proof addarray-addaray (previous step)

0 ≤ i ⊦ (rk ∈ addarray(rk .ref, ty, i, st) ↔ rk ∈ addarray(rk .ref, ty, mklist(initial_value(ty), i→n(i)), st)) ∧ (addarray(rk .ref, ty, i, st)[rk]) = (addarray(rk .ref, ty, mklist(initial_value(ty), i→n(i)), st)[rk])

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 55:
rk = r -- sk, 0 ≤ i ⊦ (rk ∈ addarray(r, ty, i, st) ↔ rk ∈ addarray(r, ty, mklist(initial_value(ty), i→n(i)), st)) ∧ (addarray(r, ty, i, st)[rk]) = (addarray(r, ty, mklist(initial_value(ty), i→n(i)), st)[rk])

Rule argument

[speclemmaarg: ,r = rk .ref ∧ sk = rk .key ↔ rk = r -- sk ,[rk, r, sk] → [rk, r, sk] ,T ,refkey , ,elim ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ r = rk .ref ∧ sk = rk .key ↔ rk = r -- sk])], [EXTRATERMS : (rk, r, sk)]]