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Proof step 3 from proof addarray-at-other (previous step)

m < n ⊦ ¬ r ∈ refs ∧ # refs = n → (addarray(r, ty, vals, st)[refs[m] -- sk]) = st[refs[m] -- sk]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
m < # refs ⊦ (addarray(r, ty, vals, st)[refs[m] -- sk]) = st[refs[m] -- sk], refs = [], r ∈ refs

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ # refs = 0 ↔ refs = []], [CSIMPFORWARD : ⊦ m < n → n ≠ 0])]]