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Proof step 50 from proof addarray-identity (previous step)

st[r -- _type] .type = mkarraytype(ty), is_array(r, st) ⊦ addarray(r, ty, getarray(r, st), st) = st

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ st1 = st2 ↔ (∀ rk. (rk ∈ st1 ↔ rk ∈ st2) ∧ st1[rk] = st2[rk])
Proof step 49:
st[r -- _type] .type = mkarraytype(ty), is_array(r, st) ⊦ ∀ rk. (rk ∈ addarray(r, ty, getarray(r, st), st) ↔ rk ∈ st) ∧ (addarray(r, ty, getarray(r, st), st)[rk]) = st[rk]

Rule argument

[speclemmaarg: ,st1 = st2 ↔ (∀ rk. (rk ∈ st1 ↔ rk ∈ st2) ∧ st1[rk] = st2[rk]) ,[st2, st1] → [st, addarray(r, ty, getarray(r, st), st)] ,F ,store ,javastore-ostorea ,Extension ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, addarray(r, ty, getarray(r, st), st))]]