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Proof step 11 from proof addarray-is-putarray (previous step)

i→n(i1) + 1 ≠ 0, 0 ≤ i1, ∀ st, val, r, i0. i→n(i0) < i→n(i1 + 1) → (0 ≤ i0 → addarray(r, val, i0, st) = putArray(mklist(val, i→n(i0)), r, 0, st)) ⊦ (addarray(r, val, i1, st)[r -- i1 ', val]) = putArray(mklist(val, (i→n(i1) + 1) -1) + val ', r, 0, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
0 ≤ i1, ∀ st, val, r, i0. i→n(i0) < i→n(i1 + 1) → (0 ≤ i0 → addarray(r, val, i0, st) = putArray(mklist(val, i→n(i0)), r, 0, st)) ⊦ (addarray(r, val, i1, st)[r -- i1 ', val]) = putArray(mklist(val, i→n(i1)) + val ', r, 0, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m + 1 ≠ 0], [CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ (m + 1) -1 = m])]]