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Proof step 15 from proof addarray-is-putarray (previous step)

i > 0, 0 ≤ i, ∀ st, val, r, i0. i→n(i0) < i→n(i) → (0 ≤ i0 → addarray(r, val, i0, st) = putArray(mklist(val, i→n(i0)), r, 0, st)) ⊦ (addarray(r, val, i - 1, st)[r -- (i - 1) ', val]) = putArray(mklist(val, i→n(i)), r, 0, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
0 ≤ i, 0 < i, ∀ st, val, r, i0. i→n(i0) < i→n(i) → (0 ≤ i0 → addarray(r, val, i0, st) = putArray(mklist(val, i→n(i0)), r, 0, st)) ⊦ (addarray(r, val, i - 1, st)[r -- (i - 1) ', val]) = putArray(mklist(val, i→n(i)), r, 0, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i < j ∧ 0 ≤ i → 0 < j], [CSIMPSEQ : ⊦ i > j ↔ j < i])]]