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Proof step 17 from proof addarray-is-putarray (previous step)

0 ≤ i ⊦ addarray(r, val, i, st) = putArray(mklist(val, i→n(i)), r, 0, st)

User applied rule induction

And obtained the following new goals

Proof step 16:
0 ≤ i, ∀ st, val, r, i0. i→n(i0) < i→n(i) → (0 ≤ i0 → addarray(r, val, i0, st) = putArray(mklist(val, i→n(i0)), r, 0, st)) ⊦ addarray(r, val, i, st) = putArray(mklist(val, i→n(i)), r, 0, st)

Rule argument

[INDHYPARG : [STANDARDINDUCTIONTYPE : ], true, false, i→n(i), [] → [], <]

Additional information

[[CONCRETESIMPRULES : ([CSIMPLESSPRED : <])], [EXTRATERMS : (i→n(i))]]