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Proof step 12 from proof addarray-lastrec (previous step)

⊦ vals = [], addarray(r, vals, i, st) = (addarray(r, vals .butlast, i, st)[r -- (i + n→i(# vals) - 1) ', vals .last])

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 11:
i + n→i(# vals) = i0 + 1 ⊦ vals = [], addarray(r, vals, i, st) = (addarray(r, vals .butlast, i, st)[r -- i0 ', vals .last])

Rule argument

[speclemmaarg: ,i0 = i - j ↔ i = i0 + j ,[i, j, i0] → [i + n→i(# vals), 1, i0] ,T ,int-abs , ,elim-sub ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ i0 = i - j ↔ i = i0 + j])], [EXTRATERMS : (i + n→i(# vals), 1, i0)]]